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文章目录1001 害死人不偿命的(3n+1)猜想1002 写出这个数1003 我要通过！1004 成绩排名1005 继续(3n+1)猜想 1001 害死人不偿命的(3n+1)猜想 将奇数情况转换为偶数，最后只对偶数做除二处理。 #include<stdio.h> int main() { int n, count = 0; scanf("%d",&n); ...

Two Sum Difficulty: Easy Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and y...

1006 换个格式输出整数 首先判断输入数字的位数，然后分情况输出即可。 #include<stdio.h> int main() { int n; scanf("%d", &n); int signB, signS; signB = signS = 0; if (n >= 100) signB = signS ...