利用折半查找法实现猜数字小游戏
折半查找又称二叉查找
算法实现如下
#define _CRT_SECURE_NO_WARNINGS 1
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
void menu()
{
printf("**************************\n");
printf("**********1.play**********\n");
printf("**********0.exit**********\n");
printf("**************************\n");
}
void game()
{
int random_num = rand() % 100 + 1;
int input = 0;
while (1)
{
printf("请输入猜的数字>:");
scanf_s("%d", &input);
if (input > random_num)
{
printf("猜大了\n");
}
else if (input < random_num)
{
printf("猜小了\n");
}
else
{
printf("恭喜你,猜对了\n");
break;
}
}
}
int main()
{
int input = 0;
srand((unsigned)time(NULL));
do
{
menu();
printf("请选择>:");
scanf("%d", &input);
switch (input)
{
case 1:
game();
break;
case 0:
break;
default:
printf("选择错误,请重新输入!\n");
break;
}
} while (input);
return 0;
}