思路:
模拟即可
#include<iostream>
using namespace std;
const int N = 220;
int like[N];
int cnt[N];
int n,m;
int main(){
cin>>n>>m;
for(int i=1;i<=n;i++){
cin>>like[i];
cnt[like[i]]++;
}
for(int i=1;i<=n;i++){
if(cnt[like[i]]==1) cout<<"BeiJu"<<endl;
else cout<<cnt[like[i]]-1<<endl;
}
return 0;
}