广搜
理解:从起点往可达方位往外扩散,每次步数+1;
基本代码(来自白书)
这里用的pair 个人更喜欢用结构体
const int INF=100000000;
typedef pair<int,int>p;
char maze[MAX_N][MAX_M+1];
int N,M;
int sx,sy;
int gx,gy;
int d[MAX_N][MAX_M];
int dx[4]={1,0,-1,0},dy[4]={0,1,0,-1};
int bfs()
{
queue<P>que;
for(int i=0;i<N;i++)
for(int j=0;j<M;j++)
d[i][j]=INF;
que.push(P(sx,sy));
d[sx][sy]=0;
while(que.size())
{
P p=que.front();que.pop();
if(p.first==gx&&p.second==gy) break;
for(int i=0;i<4;i++)
{
int nx=p.first+dx[i],ny=p.second+dy[i];
if(0<=nx&&nx<N&&0<=ny&&ny<M&&maze[nx][ny]!='#'&&d[nx][ny]==INF)
{
que.push(p(nx,ny));
d[nx][ny]=d[p.first][p.second]+1;
}
}
}
return d[gx][gy];
}
void solve()
{
int res=dfs();
cout<<res<<endl;
}
题目:
https://blog.youkuaiyun.com/weixin_43540515/article/details/90724436)
https://blog.youkuaiyun.com/weixin_43540515/article/details/90723427