数据类型与输出格式不一致时，附ASCII码表

尝试分析下以下代码的输出结果。

#include <iostream>
#include <string.h>
using namespace std;


int main() 
{ 
   char index = 1;
   
   char c_nums[6] = {'A', '0', '1', '2', '3', '4'};
   int  i_nums[6] = {65, 0, 1, 2, 3, 4};
   
   char c_twos[3][6];
   int  i_twos[3][6];
   
   memcpy(c_twos[index], c_nums, sizeof(char)*6);
   memcpy(i_twos[index], i_nums, sizeof(int)*6);
   
   printf(" c_twos[%d] char printf as char = %c,%c,%c,%c,%c,%c\n", 
   index, c_twos[index][0], c_twos[index][1], c_twos[index][2], 
   c_twos[index][3],   c_twos[index][4], c_twos[index][5]);
   
   printf(" i_twos[%d] int printf as int = %d,%d,%d,%d,%d,%d\n", 
   index, i_twos[index][0], i_twos[index][1], i_twos[index][2], 
   i_twos[index][3], i_twos[index][4], i_twos[index][5]);
   
   printf(" c_twos[%d] char printf as int = %d,%d,%d,%d,%d,%d\n", 
   index, c_twos[index][0], c_twos[index][1], c_twos[index][2], 
   c_twos[index][3], c_twos[index][4], c_twos[index][5]);
    
   printf(" i_twos[%d] int printf as char = %c,%c,%c,%c,%c,%c\n", 
   index, i_twos[index][0], i_twos[index][1], i_twos[index][2], 
   i_twos[index][3], i_twos[index][4], i_twos[index][5]);
   
   return 0;
}

运行结果

原因请参考下面的表格：