- 报错原因:在MySQL中不能在同一条SQL中查询出一张表的某些值,再直接用这些值更新或删除这张表。
- 解决方案:将查询出的结果用SELECT再查询一次,得到一张额外的临时表,再用临时表的值做更新或删除。
报错语句:
delete from person where id in (select id from (select max(id) as id from person group by email having count(id)>1) a);
解决后:
delete from person where id not in (select id from (select min(id) as id from person group by email) a);