// 解法一:递归
class Solution {
public:
TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q) {
if(root==nullptr)
return nullptr;
if(p->val < root->val && q->val < root->val)
return lowestCommonAncestor(root->left, p, q);
else if(p->val > root->val && q->val > root->val)
return lowestCommonAncestor(root->right, p, q);
return root;
}
};
// 解法二:类似二分法查找
class Solution {
public:
TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q) {
TreeNode* ans=root;
while(true){
if(p->val<ans->val && q->val<ans->val){
ans=ans->left;
}
else if(p->val>ans->val && q->val>ans->val){
ans=ans->right;
}
else{
break;
}
}
return ans;
}
};
// 解法三:未利用二叉搜索树的性质
class Solution {
public:
TreeNode* ans;
bool dfs(TreeNode* root, TreeNode* p, TreeNode* q){
if(root==nullptr) return false;
int lson=dfs(root->left,p,q);
int rson=dfs(root->right,p,q);
if((lson&&rson) || ((root->val==p->val || root->val==q->val) && (lson || rson))){
ans=root;
}
return lson || rson || (root->val==p->val || root->val==q->val);
}
TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q) {
dfs(root, p, q);
return ans;
}
};