1365. 有多少小于当前数字的数字 Python3

class Solution:
    def smallerNumbersThanCurrent(self, nums: List[int]) -> List[int]:
        
        l=[]
        for i in range(len(nums)):
            count=0
            j=0
            while j<len(nums):
                if nums[i]>nums[j]:
                    count+=1
                j+=1
            l.append(count)


        return l