点击弹出table页面,可以搜索,话不多说直接上代码
html页面如下:
<div class="layui-form-item">
<label class="layui-form-label required">选择商品</label>
<div class="layui-input-block layuimini-upload">
<input id="products_title" class="layui-input layui-col-xs6" lay-verify="required" placeholder="请选择商品" >
<input id="demo" name="products_id" class="layui-input layui-col-xs6" type="hidden">
<div class="layuimini-upload-btn">
<span><a class="layui-btn layui-btn-normal" id="select_products_id"><i class="fa fa-list"></i> 选择</a></span>
</div>
</div>
</div>
点击弹出的页面效果图
//监听选中
table.on('checkbox(transfer)', function(obj){
var n=0;
var checkStatus = table.checkStatus("transfer");
n=checkStatus.data.length;
$('.tableSelect_btn_select').find('span')