Round by 0.5 steps--codewar刷题总结

thanks a lot for codewar

Round any given number to the closest 0.5 step

I.E.

solution(4.2) = 4
solution(4.3) = 4.5
solution(4.6) = 4.5
solution(4.8) = 5

Round up if number is as close to previous and next 0.5 steps.

solution(4.75) == 5

我的解决方案：

def solution(n):
    result=divmod(n,0.5)  #这一步是产生两结果，第一个是地板除0.5，第二个模0.5
    if result[1]>=0.25:   #如果模大于，往上进0.5,
        return (result[0]+1)*0.5
    else:
        return result[0]*0.5

看看别人的：

def solution(n):
    r = n % 1
    if 0 <= r < .25:
        z = 0
    elif .25 <= r < .75:
        z = .5
    else:
        z = 1
    return int(n) + z

 浮点数还可以这样写

下一个：

def solution(n):
    return int(2*n+0.5)/2