读入一个正整数 n,计算其各位数字之和,用汉语拼音写出和的每一位数字。
输入格式:
每个测试输入包含 1 个测试用例,即给出自然数 n 的值。这里保证 n 小于 10100。
输出格式:
在一行内输出 n 的各位数字之和的每一位,拼音数字间有 1 空格,但一行中最后一个拼音数字后没有空格。
输入样例:
1234567890987654321123456789
输出样例:
yi san wu
#include <iostream>
#include <string>
using namespace std;
int main(int argc, char const *argv[])
{
/* code */
int val = 0;
string ret;
string ret1;
cin>>ret;
if (ret.size() == 0)
{
/* code */
return 0;
}
for (int i = 0; i < ret.size(); ++i)
{
/* code */
val = val + (ret[i] - 48);
}
while(val)
{
int tmp = val % 10;
val /= 10;
switch(tmp)
{
case 0:
{
ret1 = "ling " + ret1;
break;
}
case 1:
{
ret1 = "yi " + ret1;
break;
}
case 2:
{
ret1 = "er " + ret1;
break;
}
case 3:
{
ret1 = "san " + ret1;
break;
}
case 4:
{
ret1 = "si " + ret1;
break;
}
case 5:
{
ret1 = "wu " + ret1;
break;
}
case 6:
{
ret1 = "liu " + ret1;
break;
}
case 7:
{
ret1 = "qi " + ret1;
break;
}
case 8:
{
ret1 = "ba " + ret1;
break;
}
case 9:
{
ret1 = "jiu " + ret1;
break;
}
}
}
ret1.erase(ret1.size() - 1, 1);
cout<<ret1<<endl;
return 0;
}