complie和findall

from re import compile
k=[
    'a :188-8888-9999',
    'b :199-2222-0000',
    'c :101-4332-6324',
    'd :111-1112-1112;111-1111-1111'
]
n_max=len(k)
phone_num=compile(r'\d\d\d-\d\d\d\d-\d\d\d\d')
for n in range(0,n_max):
    mo=phone_num.search(k[n])
    mo1=phone_num.findall(k[n])
    print(mo.group())
    print(mo1)