通过post传参访问HTTP接口

最新推荐文章于 2024-10-14 14:00:00 发布

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最新推荐文章于 2024-10-14 14:00:00 发布

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CC 4.0 BY-SA版权

文章标签： .net

本文链接：https://blog.youkuaiyun.com/weixin_40068689/article/details/79744995

本文介绍了一个使用C#实现的HTTP POST请求方法。该方法通过指定URL及数据内容发送POST请求，并接收服务器返回的数据。文中详细展示了如何设置请求头、发送数据及读取响应。

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private string ReadHTTPForPostUrl(string queryUrl, string data, string contentType)
{
string _content = "";
try
{
data = data.Replace("&ActionDataPost", "");
HttpWebRequest request = WebRequest.Create(queryUrl) as HttpWebRequest;
if (data != null && data.Length > 0)
{
byte[] post_bytes = System.Text.Encoding.UTF8.GetBytes(data);
request.Method = "POST";
request.ContentType = contentType;
request.ContentLength = post_bytes.Length;
System.IO.Stream outStream = request.GetRequestStream();
outStream.Write(post_bytes, 0, post_bytes.Length);
outStream.Close();
queryUrl += "?post->>>>" + data;
}
else
{
queryUrl += "?" + data;
}
HttpWebResponse response = request.GetResponse() as HttpWebResponse;

StreamReader sr = new StreamReader(response.GetResponseStream());
_content = sr.ReadToEnd();
}
catch (Exception ex)
{
_content = ex.Message;
}
return _content;
}