java 检测表情符号_java 判断字符串中是否包含emoj表情及过滤。

该博客介绍了一个Java工具类`EmojiFilter`,用于检测字符串中是否包含emoji表情,并提供过滤emoji的功能。通过遍历字符串并判断Unicode范围,确定是否为表情符号。同时附带了测试代码进行演示。

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package com.luo.dtqjh.utils;

import org.apache.commons.lang.StringUtils;

public class EmojiFilter {

public static boolean containsEmoji(String source) {

int len = source.length();

boolean isEmoji = false;

for (int i = 0; i < len; i++) {

char hs = source.charAt(i);

if (0xd800 <= hs && hs <= 0xdbff) {

if (source.length() > 1) {

char ls = source.charAt(i + 1);

int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;

if (0x1d000 <= uc && uc <= 0x1f77f) {

return true;

}

}

} else {

// non surrogate

if (0x2100 <= hs && hs <= 0x27ff && hs != 0x263b) {

return true;

} else if (0x2B05 <= hs && hs <= 0x2b07) {

return true;

} else if (0x2934 <= hs && hs <= 0x2935) {

return true;

} else if (0x3297 <= hs && hs <= 0x3299) {

return true;

} else if (hs == 0xa9 || hs == 0xae || hs == 0x303d

|| hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c

|| hs == 0x2b1b || hs == 0x2b50 || hs == 0x231a) {

return true;

}

if (!isEmoji && source.length() > 1 && i < source.length() - 1) {

char ls = source.charAt(i + 1);

if (ls == 0x20e3) {

return true;

}

}

}

}

return isEmoji;

}

private static boolean isEmojiCharacter(char codePoint) {

return (codePoint == 0x0) || (codePoint == 0x9) || (codePoint == 0xA)

|| (codePoint == 0xD)

|| ((codePoint >= 0x20) && (codePoint <= 0xD7FF))

|| ((codePoint >= 0xE000) && (codePoint <= 0xFFFD))

|| ((codePoint >= 0x10000) && (codePoint <= 0x10FFFF));

}

/**

* 过滤emoji 或者 其他非文字类型的字符

*

* @param source

* @return

*/

public static String filterEmoji(String source) {

if (StringUtils.isBlank(source)) {

return source;

}

StringBuilder buf = null;

int len = source.length();

for (int i = 0; i < len; i++) {

char codePoint = source.charAt(i);

if (isEmojiCharacter(codePoint)) {

if (buf == null) {

buf = new StringBuilder(source.length());

}

buf.append(codePoint);

}

}

if (buf == null) {

return source;

} else {

if (buf.length() == len) {

buf = null;

return source;

} else {

return buf.toString();

}

}

}

}

附上测试代码

public class Test {

public static void main(String[] args) {

String string = "��都嗨��、齐静��给你��";

System.out.println(EmojiFilter.containsEmoji(string));

System.out.println(EmojiFilter.filterEmoji(string));

}

}

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