[51nod] #2108 排序100

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最新推荐文章于 2022-03-31 10:51:46 发布

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分类专栏：西建大

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这篇博客介绍了排序100问题，包括输入输出格式和约束条件，并详细探讨了八种不同的排序算法：冒泡排序、插入排序、部分排序、希尔排序、归并排序、简单快速排序、原地快速排序和堆排序。每种算法都提供了伪代码和对应的C++实现。此外，还提及了计数排序，但由于其适用范围限制，该问题未采用。

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排序100

Problem

protal:排序100

Description

Enter an array of length n to rank him in ascending order. that is, for any adjacent two number a[i], a[i+1], a[i] $\leq$ a[i+1]

Standard Input

The first line is an integer n, which indicates the length of the array.
Next n lines, each line an integer a[i], indicating the contents of the array.

Standard Output

The first line of the Output indicates the length of the array.
The next n lines indicate the sort result.

Constraints

1 $\leq$ n $\leq$ 100
1 $\leq$ a[ j ] $\leq$ 10⁹

Sample

Input

Output

Solution

Bubble Sort

pseudocode form Aizu OJ

BubbleSort(A)
for i = 0 to A.length-1
    for j = A.length-1 downto i+1
        if A[j] < A[j-1]
            swap A[j] and A[j-1]

cpp

#include <iostream>
using namespace std;
int main(void)
{
	int n, a[100], i, j;
	cin >> n;
	for (i = 0; i < n; i++)
		cin >> a[i];

	int temp;
	for (i = 0; i < n; i++)
	{
		for (j = n - 1; j > i; j--)
		{
			if (a[j] < a[j - 1])
			{
				temp = a[j];
				a[j] = a[j-1];
				a[j-1] = temp;
			}
		}
	}
	
	cout << n << endl;
	for (i = 0; i < n; i++)
		cout << a[i] << endl;
}

Bubble Sort

Insertion sort

pseudocode from wikipedia

i ← 1
while i < length(A)
    j ← i
    while j > 0 and A[j-1] > A[j]
        swap A[j] and A[j-1]
        j ← j - 1
    end while
    i ← i + 1
end while

cpp

#include <iostream>
using namespace std;
int main(void) 
{
	int n, a[100], i, j, temp;
	cin >> n;
	cin >> a[0];
	for (i = 1; i < n; i++)
	{
		cin >> temp;
		for (j = i - 1; j >= 0; j--)
		{
			if (temp >= a[j])
			{
				a[j + 1] = temp;
				break;
			}
			else
			{
				a[j + 1] = a[j];
				continue;
			}
		}
		if (j == -1)
			a[0] = temp;
	}
	cout << n << endl;
	for (i = 0; i < n; i++)
		cout << a[i] << endl;
}

insertion sort

Section sort

pseudocode from Aizu OJ

SelectionSort(A)
for i = 0 to A.length-1
    mini = i
    for j = i to A.length-1
        if A[j] < A[mini]
            mini = j
    swap A[i] and A[mini]

cpp

#include <iostream>
using namespace std;
int main(void)
{
	int n, a[100], i, j;

	cin >> n;
	for (i = 0; i < n; i++)
		cin >> a[i];

	// Setion sort 
	int mini, temp;
	for (i = 0; i < n; i++)
	{
		mini = i;
		for (j = i; j < n; j++)
		{
			if (a[j] < a[mini])
				mini = j;
		}
		temp = a[i];
		a[i] = a[mini];
		a[mini] = temp;
	}

	// Output
	cout << n << endl;
	for (i = 0; i < n; i++)
		cout << a[i] << endl;
}

Setion sort
Java

// Section Sort
import java.util.Scanner;

public class Sort100 {
	public static void main(String[] args) {
		Scanner cin = new Scanner(System.in);
		int n, i, j;
		int[] a = new int[100];

		n = cin.nextInt();
		for (i = 0; i < n; i++)
			a[i] = cin.nextInt();

		for (i = 0; i < n; i++) {
			int mini = i;
			for (j = i + 1; j < n; j++) {
				if (a[j] < a[mini])
					mini = j;
			}
			int temp = a[i];
			a[i] = a[mini];
			a[mini] = temp;
		}

		System.out.println(n);
		for (i = 0; i < n; i++) {
			System.out.println(a[i]);
		}
	}
}

Section Sort_by Java

Shell Sort

pseudocode form Aizu OJ slightly modified

insertionSort(A, n, g)
    for i = g to n-1
        v = A[i]
        j = i - g
        while j >= 0 && A[j] > v
            A[j+g] = A[j]
            j = j - g
        A[j+g] = v

shellSort(A, n)
    m = ?
    G[] = {?, ?,..., ?}
    for i = 0 to m-1
        insertionSort(A, n, G[i])

cpp

#include <iostream>
using namespace std;
int main(void)
{
	int n, a[100], i, j;
	cin >> n;
	for (i = 0; i < n; i++)
		cin >> a[i];

	int g, v;
	for (g = n / 2; g > 0; g = g / 2)
	{
		for (i = g; i < n; i++)
		{
			v = a[i];
			for (j = i - g; j >= 0 && a[j] > v; j -= g)
				a[j + g] = a[j]; 
			a[j + g] = v;
		}
	}

	cout << n << endl;
	for (i = 0; i < n; i++)
		cout << a[i] << endl;
}

Shell Sort

Merge Sort

pseudocode from Aizu OJ

Merge(A, left, mid, right)
  n1 = mid - left;
  n2 = right - mid;
  create array L[0...n1], R[0...n2]
  for i = 0 to n1-1
    do L[i] = A[left + i]
  for i = 0 to n2-1
    do R[i] = A[mid + i]
  L[n1] = SENTINEL
  R[n2] = SENTINEL
  i = 0;
  j = 0;
  for k = left to right-1
    if L[i] <= R[j]
      then A[k] = L[i]
           i = i + 1
      else A[k] = R[j]
           j = j + 1

Merge-Sort(A, left, right){
  if left+1 < right
    then mid = (left + right)/2;
         call Merge-Sort(A, left, mid)
         call Merge-Sort(A, mid, right)
         call Merge(A, left, mid, right)

cpp

// Program name: Merge Sort
// Written by: by_sknight
// Date: 2019/3/12

#include <iostream>
#include <climits>
using namespace std;

void merge(int A[], int left, int mid, int right);
void mergeSort(int A[], int left, int right);

int main(void)
{
	int n, a[100], i;
	cin >> n;
	for (i = 0; i < n; i++)
		cin >> a[i];

	mergeSort(a, 0, n);	// 直接调用合并排序

	cout << n << endl;
	for (i = 0; i < n; i++)
		cout << a[i] << endl;
}

void mergeSort(int A[], int left, int right)
{
	// 当被拆分到仅剩余一个元素时, 不需要拆分
	if (right - left <= 1)
		return;
	// 递归调用继续拆分
	int mid = (left + right) / 2;
	mergeSort(A, left, mid);	// 拆分左边并排序左边, 注意, 不会处理下标为mid的元素
	mergeSort(A, mid, right);	// 拆分右边并排序右边, 会处理下标为mid的元素
	merge(A, left, mid, right);	// 合并两个相邻的已排序数组
	return;
}

void merge(int A[], int left, int mid, int right)
{
	int i, j, k;
	// 统计左右数组的长度
	int n1, n2;
	n1 = mid - left;
	n2 = right - mid;
	// 分配临时空间存储左右数组内容, 并在末尾添加哨兵INT_MAX
	int L[n1 + 1], R[n2 + 1];
	for (i = 0; i < n1; i++)
		L[i] = A[left + i];
	L[i] = INT_MAX;
	for (i = 0; i < n2; i++)
		R[i] = A[mid + i];
	R[i] = INT_MAX;
	// 比较左右数组, 较小的扔前面
	i = 0, j = 0;
	for (k = left; k < right; k++)
	{
		if (L[i] < R[j])
		{
			A[k] = L[i];
			i++;
		}
		else
		{
			A[k] = R[j];
			j++;
		}
	}
	return;
}

Merge Sort
reward
if you want to use INT_MAX, you need #include <climits>

Quick Sort(Simple)

pseudocode from wikipedia

 function quicksort(q)
 {
     var list less, pivotList, greater
     if length(q) ≤ 1 
         return q
     else 
     {
         select a pivot value pivot from q
         for each x in q except the pivot element
         {
             if x < pivot then add x to less
             if x ≥ pivot then add x to greater
         }
         add pivot to pivotList
         return concatenate(quicksort(less), pivotList, quicksort(greater))
     }

cpp

// Program name: Quick Sort (simple)
// Written by: by_sknight
// Date: 2019/3/12

#include <iostream>
using namespace std;

void quickSort(int A[], int length);

int main(void)
{
	int n, a[100], i;
	cin >> n;
	for (i = 0; i < n; i++)
		cin >> a[i];

	quickSort(a, n);

	cout << n << endl;
	for (i = 0; i < n; i++)
		cout << a[i] << endl;
}

void quickSort(int A[], int length)
{
	// 当待排序数组长度为1时, 视为已排序数组
	if (length <= 1)
		return;
	int i;
	int pivot = A[0];	// 就以首元素作为基准值
	// 开辟额外的空间存储基准值两边的值
	int less[length], greater[length], lessNum = 0, greaterNum = 0;
	for (i = 1; i < length; i++)
	{
		if (A[i] < pivot)
		{
			less[lessNum] = A[i];
			lessNum++;
		}
		else
		{
			greater[greaterNum] = A[i];
			greaterNum++;
		}
	} // 分配完毕
	quickSort(less, lessNum);
	quickSort(greater, greaterNum);
	// 将小于基准, 基准, 大于基准的所有数组装起来
	for (i = 0; i < lessNum; i++)
		A[i] = less[i];
	A[lessNum] = pivot;
	for (i = 0; i < greaterNum; i++)
		A[lessNum + 1 + i] = greater[i];
	return;
}

Quick Sort Simple

Quick Sort (in-place)

pseudocode from wikipedia

 function partition(a, left, right, pivotIndex)
 {
     pivotValue := a[pivotIndex]
     swap(a[pivotIndex], a[right]) // 把pivot移到結尾
     storeIndex := left
     for i from left to right-1
     {
         if a[i] < pivotValue
          {
             swap(a[storeIndex], a[i])
             storeIndex := storeIndex + 1
          }
     }
     swap(a[right], a[storeIndex]) // 把pivot移到它最後的地方
     return storeIndex
 }
 procedure quicksort(a, left, right)
     if right > left
         select a pivot value a[pivotIndex]
         pivotNewIndex := partition(a, left, right, pivotIndex)
         quicksort(a, left, pivotNewIndex-1)
         quicksort(a, pivotNewIndex+1, right)

cpp

// program name: quick sort (in-place)
// Written by: by_sknight
// Date: 2019/3/13
#include <iostream>
using namespace std;

void qsort(int A[], int left, int right);
void swap(int &a, int &b);

int main(void)
{
	int n, a[100], i;
	cin >> n;
	for (i = 0; i < n; i++)
		cin >> a[i];

	qsort(a, 0, n);

	cout << n << endl;
	for (i = 0; i < n; i++)
		cout << a[i] << endl;
}

void qsort(int A[], int left, int right)
{
	if (right - left <= 1)
		return;
	int i, sotreIndex;
	int pivot = A[right - 1];
	for (i = left, sotreIndex = left; i < right - 1; i++)
	{
		if (A[i] < pivot)
		{
			swap(A[i], A[sotreIndex]);
			sotreIndex++;
		}
	}
	swap(A[right - 1], A[sotreIndex]);
	qsort(A, left, sotreIndex);
	qsort(A, sotreIndex + 1, right);
}

void swap(int &a, int &b)
{
	int temp = a;
	a = b;
	b = temp;
}

quickSort inplace

Heap Sort

pseudocode from 《编程珠玑》第2版修订版

void siftup(n)
		pre n > 0 && heap(1, n-1)
		post heap(1, n)
	i = n
	loop
		/* invariant: heap(1, n) except perhaps
			between i and its parent */
		if i == 1
			break
		p = i / 2
		if x[p] <= x[i]
			break
		swap(p, i)
		i = p

void siftdown(n)
		pre heap(2, n) && n >= 0
		post heap(1, n)
	i = 1
	loop
		/* invatiant: heap(1, n) except perhaps between
			i and its (0, 1 or 2) children */
		c = 2*i
		if c > n
			break
		/* c is the left child of i */
		if c+1 <= n
			/* c+1 is the right child of i */
			if x[c+1] < x[c]
				c++
		/* c is the lesser child of i */
		if x[i] <= x[c]
			break
		swap(c, i)
		i = c

cpp

// Program name: Heap sort
// Written by: by_sknight
// Date: 2019/3/13
#include <iostream>
using namespace std;
void swap(int &a, int &b);
int main(void)
{
	int n, a[100], i, j, heapSize;
	cin >> n;
	cin >> a[0];
	heapSize = 1;
	for (i = 1; i < n; i++)
	{
		cin >> a[i];
		heapSize++;
		// sift up
		j = i;
		while (j != 0 && a[(j-1)/2] < a[j])	// 当存在父节点且父节点小于子节点
		{
			swap(a[j], a[(j-1)/2]);
			j = (j - 1) / 2;
		}
	}
	// 此时大根堆已经创建完毕
	while (heapSize != 1)
	{
		swap(a[0], a[heapSize-1]);
		heapSize--;
		// sift down
		i = 0;
		while (2*i+1 < heapSize) // 当存在子节点
		{
			if (2*i+2 < heapSize) // 存在左右子节点, 选择最大的交换, 如果子节点小于该节点, 则该堆已排序
			{
				if (a[2*i+1] >= a[2*i+2] && a[2*i+1] > a[i])
				{
					swap(a[2*i+1], a[i]);
					i = 2*i+1;
				}
				else if (a[2*i+1] < a[2*i+2] && a[2*i+2] > a[i])
				{
					swap(a[2*i+2], a[i]);
					i = 2*i+2;
				}
				else
					break;
			}
			else	// 只有左子节点
			{
				if (a[2*i+1] > a[i])	// 左子节点更大时交换
				{
					swap(a[2*i+1], a[i]);
					i = 2*i+1;
				}
				else	// 该堆已排序
					break;
			}
		}
	}
	cout << n << endl;
	for (i = 0; i < n; i++)
		cout << a[i] << endl;
}

void swap(int &a, int &b)
{
	int temp = a;
	a = b;
	b = temp;
}

heap sort

Count Sort

description
Count Sorting is suitable for arrays with small data ranges and high densities, so the submission of this question did not pass.
cpp

// program name: countSort
// Written by: by_sknight
// Date: 2018/3/14

#include <iostream>
using namespace std;

int main(void) 
{
	int n, *arr, *count, i, j, max = 0;
	cin >> n;
	arr = new int[n];
	for (i = 0; i < n; i++)
	{
		cin >> arr[i];
		if (arr[i] > max)
			max = arr[i];
	}
	count = new int[max + 1];
	// 初始化计数数组
	for (i = 0; i < max + 1; i++)
		count[i] = 0;
	// 统计数量
	for (i = 0; i < n; i++)
		count[arr[i]]++;
	// 按照从小到大的顺序存到原数组
	for (i = 0, j = 0; i < n; i++)
	{
		while (count[j] == 0)
			j++;
		arr[i] = j;
		count[j]--;
	}

	cout << n << endl;
	for (i = 0; i < n; i++)
		cout << arr[i] << endl;
}

count sort