python遇到错误跳过_使用BeautifulSoup跳过错误404

我想用beauthulsoup删除一些网址。我正在抓取的URL来自googleanalytics API调用，其中一些不能正常工作，所以我需要找到一种方法跳过它们。在

我试着补充一下：except urllib2.HTTPError:

continue

但我遇到了以下语法错误：

^{pr2}$

以下是我的完整代码：rawdata = []

urllist = []

sharelist = []

mystring = 'http://www.konbini.com'

def print_results(results):

# Print data nicely for the user.

if results:

for row in results.get('rows'):

rawdata.append(row[0])

else:

print 'No results found'

urllist = [mystring + x for x in rawdata]

for row in urllist:

# query the website and return the html to the variable 'page'

page = urllib2.urlopen(row)

except urllib2.HTTPError:

continue

soup = BeautifulSoup(page, 'html.parser')

# Take out the

of name and get its value

name_box = soup.find(attrs={'class': 'nb-shares'})

if name_box is None:

continue

share = name_box.text.strip() # strip() is used to remove starting and trailing

# save the data in tuple

sharelist.append((row,share))

print(sharelist)