python中组合框_python tkinter组合框/按钮

我刚开始使用python和tkinter，我已经创建了一个gui，它有两个组合框和“run”按钮，其中包含两个不同的选项“SPMI”和“RFFE”。我希望我的脚本做的是，当我选择不同的选项并单击“运行”时，它应该运行SPMI.py或者报价单.py文件。在

请帮忙，谢谢

我的代码：import sys

from Tkinter import *

def callback1():

os.system('SPMI.py')

def callback2():

os.system('RFFE.py')

class MyOptionMenu(OptionMenu):

def __init__(self, master, status, *options):

self.var = StringVar(master)

self.var.set(status)

OptionMenu.__init__(self, master, self.var, *options)

self.config(font=('calibri',(10)),bg='white',width=12,fg='dark red')

self['menu'].config(font=('calibri',(10)),bg='white',fg='dark blue')

b1_1 = Button(Dragonfly, text = "Run", fg='blue',command=callback1)

b1_1.place(x=85,y=150)

b2_2= Button(Dragonfly, text = "Run", fg='blue',command=callback2)

b2_2.place(x=275,y=150)

Dragonfly = Tk()

Dragonfly.geometry('400x400+400+300')

Dragonfly.title('Dragonfly')

mainlabel = Label(text='Dragonfly Trigger Test',font=('calibri',(14)),fg='dark blue').pack()

mymenu1 = MyOptionMenu(Dragonfly, 'Select Protocol', 'SPMI','RFFE')

mymenu2 = MyOptionMenu(Dragonfly, 'Select Protocol', 'SPMI','RFFE')

mymenu1.place(x=40,y=100)

mymenu2.place(x=230,y=100)

m1label = Label(text='Frame Trigger',font=('calibri',(12)),fg='dark green').place(x=57,y=60)

m1labe2 = Label(text='External Trigger',font=('calibri',(12)),fg='dark green').place(x=240,y=60)

Dragonfly.mainloop()