59. 获取有奖金的员工相关信息

题目描述

获取有奖金的员工相关信息。
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
create table emp_bonus(
emp_no int not null,
recevied datetime not null,
btype smallint not null);
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL, PRIMARY KEY (`emp_no`,`from_date`));
给出emp_no、first_name、last_name、奖金类型btype、对应的当前薪水情况salary以及奖金金额bonus。 bonus类型btype为1其奖金为薪水salary的10%，btype为2其奖金为薪水的20%，其他类型均为薪水的30%。 当前薪水表示to_date='9999-01-01'
输出格式:

emp_no	first_name	last_name	btype	salary	bonus
10001	Georgi	Facello	1	88958	8895.8
10002	Bezalel	Simmel	2	72527	14505.4
10003	Parto	Bamford	3	43311	12993.3
10004	Chirstian	Koblick	1	74057	7405.7

select
  e.emp_no,
  e.first_name,
  e.last_name,
  eb.btype,
  s.salary,
  (
      case eb.btype
      when 1 then salary * 0.1
      when 2 then salary * 0.2
      else salary * 0.3
      end
  ) as bonus
from
  employees e,
  emp_bonus eb,
  salaries s
where
  e.emp_no = eb.emp_no
and e.emp_no = s.emp_no
and s.to_date = '9999-01-01';

或者

select
  e.emp_no,
  e.first_name,
  e.last_name,
  eb.btype,
  s.salary,
  (
      case eb.btype
      when 1 then s.salary * 0.1
      when 2 then s.salary * 0.2
      else s.salary * 0.3
      end
  ) as bonus
from
  employees e
inner join emp_bonus eb on e.emp_no = eb.emp_no
inner join salaries s on e.emp_no = s.emp_no
and s.to_date = '9999-01-01';