zhf026的博客

已知带宽3kHz，数据传输速率64k bit/s，根据香农公式，C=Wlog2(1+S/N) C = Wlog_{2} (1 + S/N) C=Wlog2​(1+S/N)所以，64000=3000log2(1+S/N) 64000 = 3000 log_{2} (1+S/N) 64000=3000log2​(1+S/N)S/N=2643−1=2642244.95=2.64×106 S/N = 2^{\frac{64}{3}} - 1 = 2642244.95 = 2.64 \times 10 ^{6