2020-08-27

数组去重

1，根据某一个属性是否重复

var obj = {};

arrays = arrays.reduce(function(item, next) {

      obj[next.id] ? '' : obj[next.id] = true && item.push(next);

      return item;

   }, []);

将内容输出到浏览器控制台

for(var i =0; i<arrays.length; i++){

console.log(arrays[i])

}

2，借助于reduce函数实现去重

var arrays = [

		["id1","name李四1"],
		
		["id2","name李四1"],
		
		["id2","name李四"],
		
		["id1","name李四1"],
		
		["id5","name李四5"]

];

//对象的所有属性相同才能认为相同

   var obj = [];

   var str;

	arrays = arrays.reduce(function(item, next) {

		str = next.toString();

	   obj.indexOf(str) == -1 ? item.push(next) && obj.push(str) : '' ;

	   return item;

  }, []);

//将内容输出到浏览器控制台

for(var i =0; i<arrays.length; i++){

	console.log(arrays[i].toString())

}