Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋
times.
You may assume that the array is non-empty and the majority element always exist in the array.
class Solution(object):
def majorityElement(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
a = len(nums)
b = a /2
for x in nums:
if nums.count(x) > b:
return x
Submission Result:
Time Limit Exceeded
return sorted(nums)[len(nums)/2]