使用python软件如何关闭弹窗_如何通过按钮关闭Kivy弹出窗口？

我有一个用Kivy创建的弹出窗口，其中包含2个按钮。用户可以通过按弹出区域之外的按钮(auto_dismission=True)或单击“否”按钮来关闭弹出窗口。

选择“是”按钮，将退出整个应用程序。在

请参阅相关代码：class ExitApp(App):

def exit_confirmation(self):

# popup can only have one Widget. This can be fixed by adding a BoxLayout

self.box_popup = BoxLayout(orientation = 'horizontal')

self.box_popup.add_widget(Label(text = "Really exit?"))

self.box_popup.add_widget(Button(

text = "Yes",

on_press = ExitApp.exit,

size_hint = (0.215, 0.075)))

self.box_popup.add_widget(Button(

text = "No",

on_press = self.popup_exit.dismiss,

size_hint=(0.215, 0.075)))

self.popup_exit = Popup(title = "Exit",

content = self.box_popup,

size_hint = (0.4, 0.4),

auto_dismiss = True)

self.popup_exit.open()

def exit(self):

App.get_running_app().stop()

现在的问题在于按下“否”按钮。当按下时，代码将退出，并出现以下错误：on_press = self.popup_exit.dismiss,

AttributeError: 'Button' object has no attribute 'popup_exit'

你知道我怎样才能尽可能容易地解决这个问题吗？在