C语言程序设计-1039 到底买不买

1. 自己写的

思路跟正确答案一样，就是用数组存储，然后计数。但是我用了76位的数组，不明原因就是答案错误

#include<iostream>
using namespace std;
#include<string>

int main(){
	
	//cout << '1' - '0'<<" "<< 'z' - '0'<<" " << 'a' - '0' ;
	
	int laoban[76] = {0};

	string a, b;
	cin >> a;
	for(int i = 0; i < a.length(); i++){
		int temp = a[i] - '0';
		laoban[temp] += 1;
	}
	cin >> b;
	for(int i = 0; i < b.length(); i++){
		int temp = b[i] - '0';
		laoban[temp] -= 1;
	}
	
	
	int queshao, duoyu;
	for(int i = 0; i < 76; i++){
		if(laoban[i] < 0){
			queshao += laoban[i];
		}
		duoyu += laoban[i];
	}
	
	if(queshao < 0){
		printf("No %d", -queshao);
	}
	else{
		printf("Yes %d", duoyu);
	}
	
	return 0;
}

2. 借鉴的

https://www.jianshu.com/p/db7a5a7fef39

#include <stdio.h>

int main()
{
    char c;
    int record[128] = {0};
    while((c = getchar()) != '\n') record[(int)c]++;
    while((c = getchar()) != '\n') record[(int)c]--;

    int more = 0, less = 0;
    for(int i = 0; i < 128; i++){
        if(record[i] < 0) less += record[i];  // 改成less += record[i], 判断less 小于0， 提交失败。额， 要写成-less啊
        if(record[i] > 0) more += record[i];
    }
    if(less<0) printf("No %d", -less);
    else       printf("Yes %d", more);
     
    return 0;
}