matlab计算一元四次方程,一元四次方程解法

本文展示了使用Matlab解决一个复杂的四次方程的过程及结果,该方程涉及高次幂运算和根号表达式,通过Matlab强大的符号计算功能得到了精确解。

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不会出错的,用matlab

solve('x^4-13*x^2-5*sqrt(2)*x 36=0')

ans =

x1=1/6*3^(1/2)*((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2) 1/6*3^(1/2)*((52*(15326 15*79131^(1/2))^(1/3)*((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2)-((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2)*(15326 15*79131^(1/2))^(2/3)-601*((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2) 30*2^(1/2)*3^(1/2)*(15326 15*79131^(1/2))^(1/3))/(15326 15*79131^(1/2))^(1/3)/((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2))^(1/2)

x2=1/6*3^(1/2)*((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2)-1/6*3^(1/2)*((52*(15326 15*79131^(1/2))^(1/3)*((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2)-((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2)*(15326 15*79131^(1/2))^(2/3)-601*((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2) 30*2^(1/2)*3^(1/2)*(15326 15*79131^(1/2))^(1/3))/(15326 15*79131^(1/2))^(1/3)/((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2))^(1/2)

x3=-1/6*3^(1/2)*((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2) 1/6*i*((-156*(15326 15*79131^(1/2))^(1/3)*((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2) 3*((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2)*(15326 15*79131^(1/2))^(2/3) 1803*((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2) 90*2^(1/2)*3^(1/2)*(15326 15*79131^(1/2))^(1/3))/(15326 15*79131^(1/2))^(1/3)/((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2))^(1/2)

x4=-1/6*3^(1/2)*((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2)-1/6*i*((-156*(15326 15*79131^(1/2))^(1/3)*((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2) 3*((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2)*(15326 15*79131^(1/2))^(2/3) 1803*((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2) 90*2^(1/2)*3^(1/2)*(15326 15*79131^(1/2))^(1/3))/(15326 15*79131^(1/2))^(1/3)/((26*(15326 15*79131^(1/2))^(1/3) (15326 15*79131^(1/2))^(2/3) 601)/(15326 15*79131^(1/2))^(1/3))^(1/2))^(1/2)。

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