如果有很多action,有共同的result指向, 而且属于不同的包,那么可以继承上面的包, 然后写一个<global-results>
1. jsp显示文件:
<ol>
<li><a href="user/user?type=1">返回success</a></li>
<li><a href="user/user?type=2">返回error</a></li>
<li><a href="user/user?type=3">返回global result</a></li>
<li><a href="admin/admin">admin,继承user包</a></li>
</ol>
2. struts.xml:
<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"
"http://struts.apache.org/dtds/struts-2.0.dtd">
<struts>
<constant name="struts.devMode" value="true" />
<package name="user" namespace="/user" extends="struts-default">
<global-results>
<result name="mainpage">/main.jsp</result>
</global-results>
<action name="index">
<result>/index.jsp</result>
</action>
<action name="user" class="com.bjsxt.struts2.user.action.UserAction">
<result>/user_success.jsp</result>
<result name="error">/user_error.jsp</result>
</action>
</package>
<package name="admin" namespace="/admin" extends="user">
<action name="admin" class="com.bjsxt.struts2.user.action.AdminAction">
<result>/admin.jsp</result>
</action>
</package>
</struts>
userAction.JAVA:
package com.bjsxt.struts2.user.action;
import com.opensymphony.xwork2.ActionSupport;
public class UserAction extends ActionSupport {
private int type;
public int getType() {
return type;
}
public void setType(int type) {
this.type = type;
}
@Override
public String execute() throws Exception {
if(type == 1) return "success";
else if (type == 2) return "error";
else return "mainpage";
}
}
adminAction.java:
package com.bjsxt.struts2.user.action;
import com.opensymphony.xwork2.ActionSupport;
public class AdminAction extends ActionSupport {
@Override
public String execute() throws Exception {
return "mainpage";
}
}