输出日期下一天

最新推荐文章于 2021-06-10 18:01:37 发布

转载最新推荐文章于 2021-06-10 18:01:37 发布 · 122 阅读

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原文链接：http://www.cnblogs.com/itpoorman/p/5254476.html

本文介绍了一个使用C++实现的日期时间字符串到时间戳的转换方法，并演示了如何获取输入日期的下一天。

 1 #include <iostream>
 2 #include <stdio.h>
 3 #include <sstream>
 4 
 5 using namespace std;
 6 
 7 int main(int argc, char **argv)
 8 {
 9     int ret(0);
10 
11     string line;
12     while (getline(cin, line))
13     {
14         int year(0), month(0), day(0), hour(0), minute(0), second(0);
15         ret = sscanf(line.c_str(), "%4d-%2d-%2d %2d:%2d:%2d", &year, &month, &day, &hour, &minute, &second);
16         if (6 != ret)
17         {
18             cout << "input date format invalid, please input like 2015-12-31 10:30:00" << endl;
19             continue;
20         }
21 
22         struct tm curTm;
23         curTm.tm_year = year - 1900;
24         curTm.tm_mon = month -1;
25         curTm.tm_mday = day;
26         curTm.tm_hour = hour;
27         curTm.tm_min = minute;
28         curTm.tm_sec = second;
29 
30         time_t curDaySec = mktime(&curTm);
31         time_t lastDaySec = curDaySec + (24 * 60 * 60);
32 
33         struct tm * lastTm;
34         lastTm = localtime(&lastDaySec);
35 
36         char result[100];
37         strftime(result, sizeof(result), "%F %T", lastTm);
38         cout << "result: " << result << endl;
39     }
40 
41     return 0;
42 }

转载于:https://www.cnblogs.com/itpoorman/p/5254476.html