hdu 1075 What Are You Talking About 字典树模板

本文介绍了一个简单的火星文翻译器的实现方法,使用了字典和前缀树的数据结构来提高查找效率,能够将火星文翻译成英文。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

What Are You Talking About

Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 102400/204800 K (Java/Others)
Total Submission(s): 11730    Accepted Submission(s): 3763


Problem Description
Ignatius is so lucky that he met a Martian yesterday. But he didn't know the language the Martians use. The Martian gives him a history book of Mars and a dictionary when it leaves. Now Ignatius want to translate the history book into English. Can you help him?
 

 

Input
The problem has only one test case, the test case consists of two parts, the dictionary part and the book part. The dictionary part starts with a single line contains a string "START", this string should be ignored, then some lines follow, each line contains two strings, the first one is a word in English, the second one is the corresponding word in Martian's language. A line with a single string "END" indicates the end of the directory part, and this string should be ignored. The book part starts with a single line contains a string "START", this string should be ignored, then an article written in Martian's language. You should translate the article into English with the dictionary. If you find the word in the dictionary you should translate it and write the new word into your translation, if you can't find the word in the dictionary you do not have to translate it, and just copy the old word to your translation. Space(' '), tab('\t'), enter('\n') and all the punctuation should not be translated. A line with a single string "END" indicates the end of the book part, and that's also the end of the input. All the words are in the lowercase, and each word will contain at most 10 characters, and each line will contain at most 3000 characters.
 

 

Output
In this problem, you have to output the translation of the history book.
 

 

Sample Input
 
START
from fiwo
hello difh
mars riwosf
earth fnnvk
like fiiwj
END
START
difh, i'm fiwo riwosf.
i fiiwj fnnvk!
END
 
Sample Output
 
hello, i'm from mars.
i like earth!
 
 
Huge input, scanf is recommended.
 
 
 
  1 /*
  2 模板题
  3 
  4 */
  5 #include<iostream>
  6 #include<stdio.h>
  7 #include<cstring>
  8 #include<cstdlib>
  9 using namespace std;
 10 
 11 struct Tril
 12 {
 13     char a[20];
 14     struct Tril *next[26];
 15 };
 16 Tril *root;
 17 void mem(Tril *p)
 18 {
 19     int i;
 20     for(i=0;i<26;i++) p->next[i]=NULL;
 21     p->a[0]='\0';
 22 }
 23 
 24 void insert_Tril(char *s1,char *s2)
 25 {
 26     int i,k,ans;
 27     struct Tril *p=root,*q;
 28     k=strlen(s2);
 29     for(i=0;i<k;i++)
 30     {
 31         ans=s2[i]-'a';
 32         if( p->next[ans]==NULL )
 33         {
 34             q=(struct Tril*)malloc(sizeof(struct Tril));
 35             mem(q);
 36             p->next[ans]=q;
 37             p=q;
 38         }
 39         else
 40         {
 41             p=p->next[ans];
 42         }
 43     }
 44     strcpy(p->a,s1);
 45 }
 46 void found_Tril(char *s1)
 47 {
 48     int i,k,ans;
 49     struct Tril *p=root;
 50     bool flag=false;
 51     k=strlen(s1);
 52     for(i=0;i<k;i++)
 53     {
 54         ans=s1[i]-'a';
 55         if(p->next[ans]==NULL)
 56         {
 57             flag=true;
 58             break;
 59         }
 60         else p=p->next[ans];
 61     }
 62     if(flag==true || strlen(p->a)==0)
 63         printf("%s",s1);
 64     else printf("%s",p->a);
 65 }
 66 int main()
 67 {
 68     int i,k;
 69     char s1[3014],s2[3014];
 70     root=(struct Tril*)malloc(sizeof(struct Tril));
 71     mem(root);
 72     scanf("%s",s1);
 73     while(scanf("%s",s1))
 74     {
 75         if( strcmp(s1,"END")==0)break;
 76         scanf("%s",s2);
 77         insert_Tril(s1,s2);
 78     }
 79     scanf("%s",s1);
 80     getchar();
 81     while(gets(s1))
 82     {
 83         if( strcmp(s1,"END")==0)break;
 84         i=0;
 85         while(s1[i]!='\0')
 86         {
 87             if( s1[i]>'z'||s1[i]<'a')
 88             {
 89                 printf("%c",s1[i]);
 90                 i++;
 91             }
 92             else
 93             {
 94                 k=0;
 95                 while(s1[i]<='z'&&s1[i]>='a' &&s1[i]!='\0')
 96                 {
 97                     s2[k]=s1[i];
 98                     i++;
 99                     k++;
100                 }
101                 s2[k]='\0';
102                 found_Tril(s2);
103             }
104         }
105         printf("\n");
106     }
107     return 0;
108 }

 

 

转载于:https://www.cnblogs.com/tom987690183/p/3570057.html

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值