1036 Boys vs Girls （25 分）

最新推荐文章于 2023-06-03 11:23:30 发布

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最新推荐文章于 2023-06-03 11:23:30 发布

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原文链接：http://www.cnblogs.com/binanry/p/10013455.html

本文介绍了一个C++程序，用于从输入文件中读取学生信息，包括姓名、性别、ID和成绩，然后找出所有女性学生的最高成绩和所有男性学生的最低成绩，并计算两者之间的差异。如果某一性别学生缺失，则相应输出'Absent'，并输出'NA'代替成绩差。

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This time you are asked to tell the difference between the lowest grade of all the male students and the highest grade of all the female students.

Input Specification:

Each input file contains one test case. Each case contains a positive integer

Output Specification:

For each test case, output in 3 lines. The first line gives the name and ID of the female student with the highest grade, and the second line gives that of the male student with the lowest grade. The third line gives the difference

Sample Input 1:

3
Joe M Math990112 89
Mike M CS991301 100
Mary F EE990830 95

Sample Output 1:

Mary EE990830
Joe Math990112
6

Sample Input 2:

1
Jean M AA980920 60

Sample Output 2:

Absent
Jean AA980920
NA

#include<iostream>
#include<algorithm>
using namespace std;

struct student
{
    string name;
    char sex;
    string id;
    int grade;
};
bool cmp(student a,student b)
{
    return a.grade>b.grade;
}
int main()
{
    int n;
    vector<student> boy;
    vector<student> girl;
    student temp;
    cin>>n;
    for(int i=0;i<n;i++)
    {
        cin>>temp.name>>temp.sex>>temp.id>>temp.grade;
        if(temp.sex == 'F')
            girl.push_back(temp);
        else
            boy.push_back(temp);
       // scanf("%s%s%s%d",&stu[i].name,&stu[i].sex,&stu[i].id,&stu[i].grade);
    }
    //sort(student,student+n);
    sort(boy.begin(),boy.end(),cmp);
    sort(girl.begin(),girl.end(),cmp);
    if(girl.size()==0)
        cout<<"Absent"<<endl;
    else
        cout<<girl[0].name<<' '<<girl[0].id<<endl;
    if(boy.size()==0)
        cout<<"Absent"<<endl;
    else
        cout<<boy[boy.size()-1].name<<' '<<boy[boy.size()-1].id<<endl;
    if(girl.size() == 0 || boy.size() == 0)
        cout<<"NA"<<endl;
    else
        cout<<abs(boy[boy.size() -1].grade - girl[0].grade)<<endl;
    return 0;
}