iphone：URL initWithString 返回为空

最新推荐文章于 2025-08-10 11:30:26 发布

转载最新推荐文章于 2025-08-10 11:30:26 发布 · 88 阅读

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原文链接：https://yq.aliyun.com/articles/380654

本文介绍如何处理URL字符串中的特殊字符，特别是空格的正确转换方式。通过使用percent escape codes将空格转换为%20，并进一步进行UTF-8编码转换，确保URL符合RFC标准。

Parameters

URLString

The string with which to initialize the NSURL object. This string must conform to URL format as described in RFC 2396. This method parses URLString according to RFCs 1738 and 1808.

Discussion

This method expects URLString to contain any necessary percent escape codes, which are ‘:’, ‘/’, ‘%’, ‘#’, ‘;’, and ‘@’. Note that ‘%’ escapes are translated via UTF-8.

所以URLString中有空格的要变成：%20

[urlstring stringByReplacingOccurrencesOfString:@" "withString:@"%20"]]

然后还要进行编码转换

str=[str stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

本文转自老Zhan博客园博客，原文链接：http://www.cnblogs.com/mybkn/archive/2012/05/26/2519406.html，如需转载请自行联系原作者