python bs4 find_all_python – 在bs4.element.ResultSet对象或列表上的beautifulsoup：find_all？...

嗨所以我在一个beautifulsoup对象上应用find_all,并找到一些东西,它是一个bs4.element.ResultSet对象或一个列表.

我想在那里进一步做find_all,但是bs4.element.ResultSet对象不允许这样做.我可以循环遍历bs4.element.ResultSet对象的每个元素来执行find_all.但我可以避免循环并将其转换回beautifulsoup对象吗？

请参阅代码了解详情.谢谢

html_1 = """

ABCD

"""

soup = BeautifulSoup(html_1,'html.parser')

type(soup) #bs4.BeautifulSoup

# do find_all on beautifulsoup object

th_all = soup.find_all('th')

# the result is of type bs4.element.ResultSet or similarly list

type(th_all) #bs4.element.ResultSet

type(th_all[0:1]) #list

# now I want to further do find_all

th_all.find_all(text='A') #not work

# can I avoid this need of loop?

for th in th_all:

th.find_all(text='A') #works