HDOJ 2055 An easy problem

最新推荐文章于 2025-08-08 22:01:10 发布

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最新推荐文章于 2025-08-08 22:01:10 发布

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文章标签： java

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Problem Description
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, … f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

Input
On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.

Output
for each case, you should the result of y+f(x) on a line.

Sample Input
6
R 1
P 2
G 3
r 1
p 2
g 3

Sample Output
19
18
10
-17
-14
-4

题意：we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, … f(Z) = 26, f(z) = -26;Give you a letter x and a number y , you should output the result of y+f(x)..

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        String lowerCase = "0abcdefghijklmnopqrstuvwxyz";
        String capital = "1ABCDEFGHIJKLMNOPQRSTUVWXYZ";
        int n =sc.nextInt();
        //sc.next();
        while(n-->0){
            String strs = sc.next();
            //System.out.println(strs);
            int y = sc.nextInt();
            char x = strs.charAt(0);
            //strs = strs.substring(2);
            //int y = Integer.parseInt(strs,10);

            //System.out.println(x);
            //System.out.println(y);
            int g=0,h=0;
            for(int i=1;i<lowerCase.length();i++){
                if(x==lowerCase.charAt(i)){
                    g=-i;
                    break;
                }
            }
            for(int i=1;i<capital.length();i++){
                if(x==capital.charAt(i)){
                    h=i;
                    break;
                }
            }
            System.out.println(y+g+h);

        }

    }

}