HDOJ(HDU) 1570 A C

最新推荐文章于 2020-04-05 10:56:53 发布

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最新推荐文章于 2020-04-05 10:56:53 发布

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文章标签： java

原文链接：https://yq.aliyun.com/articles/273124

本文介绍如何解决AC问题，并复习了学校中学到的组合公式。通过实例输入输出，详细阐述了如何根据字符' A '或' C '来计算A(m,n)或C(m,n)，提供了一个简单的水题解决方案。

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Problem Description
Are you excited when you see the title “AC” ? If the answer is YES , AC it ;

You must learn these two combination formulas in the school . If you have forgotten it , see the picture.

Now I will give you n and m , and your task is to calculate the answer .

Input
In the first line , there is a integer T indicates the number of test cases.
Then T cases follows in the T lines.
Each case contains a character ‘A’ or ‘C’, two integers represent n and m. (1<=n,m<=10)

Output
For each case , if the character is ‘A’ , calculate A(m,n),and if the character is ‘C’ , calculate C(m,n).
And print the answer in a single line.

Sample Input
2
A 10 10
C 4 2

Sample Output
3628800
6

题意：很简单，看图片就能理解了。
水题一个！就不多解释了。

import java.util.Scanner;

public class Main{
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();
        while(t-->0){
            String str = sc.next();
            int n = sc.nextInt();
            int m =sc.nextInt();

            if(str.charAt(0)=='A'){
                System.out.println(a(n,m));
            }else{
                System.out.println(c(n,m));
            }

        }

    }

    private static int c(int n, int m) {
        int num =1;
        if(n-m>m){
            m=n-m;
        }
        int cnum=1;
        for(int i=1;i<=n-m;i++){
            cnum=cnum*i;
        }
        for(int i=m+1;i<=n;i++){
            num=num*i;
        }
        return num/cnum;
    }

    private static int a(int n, int m) {
        int num=1;
        for(int i=n-m+1;i<=n;i++){
            num=num*i;
        }
        return num;
    }
}