这真真是极好的

本文探讨了如何将中文短语“这真真是极好的”翻译成英文,并提供了31个不同的英文词汇来表达“极好的”这一概念。文章还提到了一个名为superword的Java软件,该软件用于分析英文单词的音近形似转化规律等。

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“这真真是极好的”该怎么翻译成英文,有多少种翻译方法呢?

“真”在这里是副词,表示“完全确实,毫无疑问”,用了两个真就是在使用堆叠效果,类似200%的用法,重点是“极好的”,英文中有多少个词可以用来表示“极好的”呢?

我在这里列出了31个,虽然他们各自有些微妙的区别,但是都可以用来表达“极好的”这个含义。

所以最终翻译为:“That's excellent. ”,excellent可以替换为下面31个词中的任何一个。

1. excellent: Something that is excellent is very good indeed.

2. marvellous: If you describe someone or something as marvellous, you are emphasizing that they are very good.

3. superb: If something is superb, its quality is very good indeed.

4. first-rate: If you say that something or someone is first-rate, you mean that they are extremely good and of the highest quality.

5. first-class: If you describe something or someone as first-class, you mean that they are extremely good and of the highest quality.

6. wonderful: If you describe something or someone as wonderful, you think they are extremely good.

7. outstanding: If you describe someone or something as outstanding, you think that they are very remarkable and impressive.

8. exceptional: You use exceptional to describe someone or something that has a particular quality, usually a good quality, to an unusually high degree.

9. magnificent: If you say that something or someone is magnificent, you mean that you think they are extremely good, beautiful, or impressive.

10. splendid: If you say that something is splendid, you mean that it is very good.

11.superlative: If you describe something as superlative, you mean that it is extremely good.

12.matchless: You can use matchless to emphasize that you think something is extremely good.

13.peerless: Something that is peerless is so beautiful or wonderful that you feel that nothing can equal it.

14.great: If you describe someone or something as great, you approve of them or admire them.

15.super: Some people use super to mean very nice or very good.

16.terrific: If you describe something or someone as terrific, you are very pleased with them or very impressed by them.

17.tremendous: You can describe someone or something as tremendous when you think they are very good or very impressive.

18.smashing: If you describe something or someone as smashing, you mean that you like them very much.

19.fantastic: If you say that something is fantastic, you are emphasizing that you think it is very good or that you like it a lot.

20.sensational: You can describe something as sensational when you think that it is extremely good.

21.stellar: A stellar person or thing is considered to be very good.

22.ace: If you say that something is ace, you think that it is good and you like it a lot.

23.fab: If you say that something is fab, you are emphasizing that you think it is very good.

24.cool: If you say that something is cool, you think it is very good.

25.awesome: An awesome person or thing is very good.

26.magic: If you say that something is magic, you think it is very good or enjoyable.

27.wicked: An wicked person or thing is very good.

28.tip-top: You can use tip-top to indicate that something is extremely good.

29.top-notch: If you describe someone or something as top-notch, you mean that they are of a very high standard or quality.

30.capital: An capital person or thing is excellent.

31.fabulous: If you describe something as fabulous, you are emphasizing that you like it a lot or think that it is very good.


superword是一个Java实现的英文单词分析软件,主要研究英语单词音近形似转化规律、前缀后缀规律、词之间的相似性规律等等。





转载于:https://my.oschina.net/apdplat/blog/533484

<think>我们参考达芬奇密码桌游的进阶玩法规则,并尝试编写一个简化的Python实现。由于规则较为复杂,我们将分步骤实现核心功能。游戏规则回顾:1.准备:24张数字牌(0-11,每个数字有黑白两色)洗混。每人抓取4张(4人游戏时3张)作为手牌,所有玩家手牌面朝下排列在桌上(自己可见对方不可见)。玩家需将手牌按数字从小到大排列,同样数字时黑牌在左(前)白牌在右(后)。2.游戏流程:轮到自己时,首先从牌堆抓一张牌(暂时不加入自己的牌列)。然后可以选择一个对手的一张牌进行猜测(猜数字0-11或Joker)。猜对则对手摊开那张牌(所有人可见),然后你可以选择继续猜(抓的牌暂时不放回)或者将抓到的牌按规则放回自己牌列(结束回合);猜错则你必须立即将刚抓的牌摊开放回自己牌列(按规则位置)。3.特殊规则:Joker可以放在任意位置,当别人猜Joker时,必须直接猜中(即直接猜Joker)才算对。4.胜利条件:当除了一位玩家外其他所有玩家的牌都被猜出(即全部摊开)时,剩下的那位玩家获胜。实现思路:我们将创建以下主要类:-Card:表示一张牌,包含数字(0-11或特殊标记Joker)和颜色(黑白,Joker没有颜色)。-Player:表示一个玩家,包含其手牌列表(按规则排序)、是否摊开的信息等。-DaVinciCodeGame:主游戏类,管理游戏流程。注意:进阶玩法中加入了Joker,我们假设牌堆中原本没有Joker,但规则中说明加入Joker牌,所以我们将Joker作为特殊牌,数量可自定(根据规则,我们只加入1张?但规则未说明数量,按照常见设置,可能为2张,我们暂定2张)。但原规则说24张数字牌,所以总牌堆为24+Joker张。由于规则中“加入Joker牌”并未说明数量,我们按照常见设置加入2张Joker(0张也可以,但规则说加入了,所以至少1张)。我们这样创建牌堆:数字牌:每个数字(0-11)有黑白两张,共24张。特殊牌:Joker牌2张(没有数字,也没有颜色,用None表示)。步骤:1.初始化游戏:创建牌堆,洗牌,初始化玩家。2.发牌:每个玩家抓取起始手牌(4张,4人游戏时为3张,这里我们先实现4人以下的情况,即默认每人4张;但实际游戏人数需要初始化时设定)。3.玩家排序自己的手牌:规则为从小到大,相同数字黑色在白色左边(即黑色在前,白色在后)。4.游戏循环,直到满足胜利条件。在游戏循环中,当前玩家执行以下动作:a)从牌堆抓一张牌(如果牌堆为空,则无法抓牌?规则未说明,我们视为游戏继续,但跳过抓牌,直接进行猜测?但规则中抓牌是必须的步骤,因此如果牌堆空了,我们可以终止游戏?或者改为玩家必须选择将某张牌放回?这里我们按照规则,抓牌是第一步,所以若牌堆空,则跳过抓牌步骤,但玩家仍然可以猜牌(此时手牌已满,但抓的牌为None,猜完后必须放回一张牌?规则没有规定,所以我们设定:如果抓牌时牌堆空,则玩家只能选择猜牌,并且猜完后必须结束回合(此时不能继续猜,因为规则说猜对后可以选择继续猜或放回,但这里没有抓到牌,所以放回步骤无法进行,所以强制结束回合?)为了避免复杂,我们假设牌堆足够大,不会空。b)猜测阶段:玩家选择一位对手和对手的一张牌(位置)以及猜的数字(或Joker)。-如果猜对:对手摊开该牌(设置该牌为可见),然后当前玩家可以选择继续猜(重复b)或者将抓到的牌放回自己的牌列(并结束回合)。注意:如果选择继续猜,则不需要放牌,但注意此时抓到的牌还在手里(临时牌),而猜牌操作可能会多次进行。-如果猜错:当前玩家必须立即将抓到的牌摊开(视为明牌)并放回自己的牌列(按规则排序位置),然后结束回合。c)放回抓到的牌:在猜对后选择结束回合时,或者猜错后,需要将抓到的牌放入自己的牌列(并排序,但放入时是摊开还是盖着?规则中,抓到的牌如果猜错是要摊开放回的,而猜对后选择放回则应该是盖着的(因为没有被猜出)?但规则中只有被猜对时才会摊开对手的牌。对于自己放回的牌,如果是猜错时,是摊开的(所有人可见);如果是猜对后主动放回,则应该是盖着的(只有自己可见?)但规则并没有明确,我们按照这样理解:-猜错时:放回的牌是摊开的(对手可见)-猜对后选择放回:放回的牌是盖着的(对手不可见)然而,规则指出“把牌按数字大小从左至右排列,数字相同则黑牌放白牌左边”,所以放回牌时,无论是否摊开,都要按顺序放置。但是,摊开与否决定了对手是否知道这张牌。因此,我们需要在Card类中记录是否摊开(revealed),在Player类中,每个玩家有一个牌列(hand),每张牌在牌列中有一个位置,并且记录是否摊开。但是,这里有一个问题:起始时玩家的牌都是盖着的,然后被猜中或者被迫放回时摊开。所以,我们设计:-Card类:value(数字或Joker),color(对于数字牌是'black'或'white',Joker为None),is_revealed(是否摊开)。-Player类:初始手牌都是盖着的(is_revealed=False)。当被猜中时,设置该牌is_revealed=True。当自己放回抓到的牌时,如果是猜错而放回,设置is_revealed=True;如果是主动结束放回,设置is_revealed=False。然后,在显示牌列时,对于其他玩家,只能看到摊开牌的数值,没摊开的只能看到是盖着的状态。5.结束条件:当一名玩家所有的牌都被摊开(即都被猜中)时,该玩家出局。直到只剩一名玩家还有未摊开的牌,该玩家获胜。然而,在回合进行中,可能一次猜牌导致多个摊开?并且,当玩家放回牌后,可能自己盖着放回,所以玩家手牌中可能有摊开的也有盖着的。判断一个玩家是否出局:只要他所有的牌都摊开了(无论位置),就算出局。实现难点:-玩家放回抓到的牌时需要插入到正确位置(排序),并且设置摊开状态。-游戏循环中,玩家操作的选择(AI?或人类输入)由于时间限制,我们实现一个简单的文本交互版本(没有AI),玩家通过输入指令操作。我们先不考虑图形界面,只实现核心逻辑。类定义:</think> 以下是为《达芬奇密码》桌游进阶玩法实现的Python代码框架,包含核心规则逻辑和关键数据结构: ### 核心数据结构与函数实现 ```python import random from enum import Enum class CardColor(Enum): BLACK = 0 WHITE = 1 JOKER = 2 # 特殊Joker牌 class Card: def __init__(self, value: int, color: CardColor): """ value: 0-11的数字, Joker值为-1 color: BLACK/WHITE/JOKER """ self.value = value self.color = color def __lt__(self, other): """定义牌的排序规则: 数值优先, 同数值黑牌<白牌""" if self.value == other.value: return self.color.value < other.color.value return self.value < other.value class Player: def __init__(self, player_id: int): self.id = player_id self.hand = [] # 手牌列表 self.revealed = [False] * 4 # 牌是否被猜中 def sort_hand(self): """按规则排序手牌: 数字升序, 同数字黑在左""" self.hand.sort() def add_card(self, card: Card): """添加新牌并重新排序""" self.hand.append(card) self.revealed.append(False) self.sort_hand() def reveal_card(self, index: int): """标记牌已被猜中""" self.revealed[index] = True ``` ### 游戏核心逻辑实现 ```python class DaVinciCodeGame: def __init__(self, num_players: int = 4): self.players = [Player(i) for i in range(num_players)] self.deck = self._create_deck() self.current_player = 0 self.drawn_card = None # 当前抓到的牌 def _create_deck(self) -> list: """创建牌组: 24张数字牌 + 2张Joker""" cards = [] # 添加数字牌 (0-11, 黑白各一) for value in range(12): for color in [CardColor.BLACK, CardColor.WHITE]: cards.append(Card(value, color)) # 添加Joker牌 cards.append(Card(-1, CardColor.JOKER)) cards.append(Card(-1, CardColor.JOKER)) return cards def setup_game(self): """游戏初始化: 洗牌, 发牌""" random.shuffle(self.deck) hand_size = 3 if len(self.players) == 4 else 4 for player in self.players: player.hand = [self.deck.pop() for _ in range(hand_size)] player.revealed = [False] * hand_size player.sort_hand() def player_turn(self): """玩家回合流程""" # 步骤1: 抓一张牌 self.drawn_card = self.deck.pop() # 步骤2: 选择对手和猜牌 (需要玩家输入/决策) target_player, card_idx, guess = self.get_player_decision() target = self.players[target_player] actual_card = target.hand[card_idx] # 特殊规则: Joker必须直接猜中 if actual_card.color == CardColor.JOKER: correct = (guess == -1) else: correct = (guess == actual_card.value) if correct: target.reveal_card(card_idx) # 猜对后可选择继续猜或放回牌 if self.player_wants_to_continue(): return False # 继续猜牌 else: self.place_card_back() else: # 猜错必须摊开并放回牌 self.drawn_card.revealed = True self.players[self.current_player].add_card(self.drawn_card) return True # 回合结束 ``` ### 运行代码可能缺失的部分 1. **玩家决策接口**: ```python def get_player_decision(self) -> tuple: """需要实现: - 玩家选择对手 (0-{num_players-1}) - 选择猜哪张牌 (0-3) - 猜牌值 (0-11 或 -1=Joker) """ # 示例: 简单随机决策 target_player = random.randint(0, len(self.players)-1) card_idx = random.randint(0, 3) guess = random.choice([-1] + list(range(12))) return target_player, card_idx, guess ``` 2. **游戏主循环**: ```python def play_game(self): self.setup_game() while not self.game_over(): print(f"玩家 {self.current_player} 的回合") turn_completed = self.player_turn() if turn_completed: self.current_player = (self.current_player + 1) % len(self.players) ``` 3. **胜利条件判断**: ```python def game_over(self): """当只剩一名玩家还有隐藏牌时游戏结束""" active_players = 0 for player in self.players: if not all(player.revealed): active_players += 1 return active_players <= 1 ``` ### 相关问题 1. 如何实现玩家决策的智能AI算法?[^1] 2. Joker牌的特殊规则在多人游戏中如何平衡?[^2] 3. 如何处理牌堆耗尽的情况?规则应如何调整?[^3] 4. 如何扩展支持更多进阶规则(如特殊能力牌)?[^1] [^1]: 可参考蒙特卡洛树搜索(MCTS)算法实现智能决策《游戏人工智能编程案例精粹》 [^2]: 卡牌游戏平衡性设计原则《平衡性设计模式》 [^3]: 桌游规则容错处理建议《现代桌游设计指南》
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