html ajax提交表单实例,jQuery使用ajaxSubmit()提交表单示例

/**

* 登录

* @return

*/

public String login() {

HttpServletRequest request= ServletActionContext.getRequest();

User cus = userService.loginByNameAndPassword(login_name,login_password);

if (cus != null && cus.getId() != null) {

request.getSession().setAttribute(WebConfig.CUSTOMER_ID,cus.getId());

request.getSession().setAttribute(WebConfig.CUSTOMER_LOGIN_NAME, cus.getLoginName());

login_result = "['success']";

} else {

login_result = "['error']";

}

return SUCCESS;

}

$(function() { $("div.panel-foot button").click(function() { var login_name = $("input[name='login_name']").val(); var s_password = $("#pwd").val(); if (login_name == null || login_name == '') { alert("请出入用户名"); return false; } if (s_password == null || s_password == '') {alert("请输入密码"); return false; } var password = hex_md5(s_password); $("input[name='login_password']").val(password); var option = { url : "/company/login.action",type : "post",dataType : "json",success : function(result) { var data = eval("(" + result + ")"); if (data == 'success') { location.href = "list.action"; } else { alert("登录失败，用户或密码不正确！"); } } }; $('#login_form').ajaxSubmit(option); return false; }); });

登录

login_result

login_result