ajax submit - jquery

function submitForm() {
            var url = "/RefRoute/InsertTemplate";

            //alert("submit");

            var options = {
                url: url,
                type: "POST",
                success: function (data) {
                    if (data == "SUCCESS") {
                        alert("更新成功!");
                    } else {
                        alert("更新失败!");
                    }
                }
            };
            
            $("#frmRouteTemplate").ajaxSubmit(options);
        }

转载于:https://www.cnblogs.com/davidgu/archive/2012/11/06/2757012.html