最近我要做一个系统,选择了Struts2,并且一个模块发布webservice服务,所以选择CXF,但是访问webservice文档时出现了这个问题
这是因为访问webservice时的请求被struts2的filter过滤掉了,解决这个问题,我是让Struts2的filter不要过滤webservice的请求,所以要改一下struts2的StrutsPrepareAndExecuteFilter
package com.lin.jllm.filter;
import java.io.IOException;
import javax.servlet.FilterChain;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.http.HttpServletRequest;
import org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter;
/**
* 继承 StrutsPrepareAndExecuteFilter,改写doFilter方法,使struts2不过滤WebService请求
* @author lin
*
*/
public class StrutsPrepareAndExecuteFilterExcludingWebService extends
StrutsPrepareAndExecuteFilter {
@Override
public void doFilter(ServletRequest req, ServletResponse res,
FilterChain chain) throws IOException, ServletException {
HttpServletRequest request = (HttpServletRequest) req;
if (request.getRequestURI().contains("webservice")) {
//如果是访问webservice,不进行过滤
chain.doFilter(req, res);
} else {
super.doFilter(req, res, chain);
}
}
}
然后在web.xml中从新配置Struts2的过滤器
<!-- 配置CXF请求Servlet -->
<servlet>
<servlet-name>CXF</servlet-name>
<servlet-class>org.apache.cxf.transport.servlet.CXFServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>CXF</servlet-name>
<url-pattern>/webservice/*</url-pattern>
</servlet-mapping>
<!-- Struts2 -->
<filter>
<filter-name>struts2</filter-name>
<filter-class>com.lin.jllm.filter.StrutsPrepareAndExecuteFilterExcludingWebService</filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
再次访问wsdl文档
OK.