[LeetCode] Fizz Buzz 嘶嘶嗡嗡

最新推荐文章于 2025-12-04 16:35:29 发布

转载最新推荐文章于 2025-12-04 16:35:29 发布 · 68 阅读

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#数据结构与算法

本文提供了一个简洁的解决方案来实现从1到n的FizzBuzz问题，对于3的倍数输出Fizz，对于5的倍数输出Buzz，同时是3和5的倍数则输出FizzBuzz。通过一个简单的C++程序展示了如何处理不同情况。

Write a program that outputs the string representation of numbers from 1 to n.

But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.

Example:

n = 15,

Return:
[
    "1",
    "2",
    "Fizz",
    "4",
    "Buzz",
    "Fizz",
    "7",
    "8",
    "Fizz",
    "Buzz",
    "11",
    "Fizz",
    "13",
    "14",
    "FizzBuzz"
]

这道题真心没有什么可讲的，就是分情况处理就行了。

class Solution {
public:
    vector<string> fizzBuzz(int n) {
        vector<string> res;
        for (int i = 1; i <= n; ++i) {
            if (i % 15 == 0) res.push_back("FizzBuzz");
            else if (i % 3 == 0) res.push_back("Fizz");
            else if (i % 5 == 0) res.push_back("Buzz");
            else res.push_back(to_string(i));
        }
        return res;
    }
};