LeetCode-Fizz Buzz

最新推荐文章于 2022-04-12 18:12:35 发布

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本文深入解析了经典的编程面试题——FizzBuzz问题，介绍了如何使用Java编程语言实现该问题的解决方案，通过判断数字是否为3、5或两者的倍数来输出特定字符串。

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Description：
Write a program that outputs the string representation of numbers from 1 to n.

But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.

Example:

n = 15,

Return:
[
    "1",
    "2",
    "Fizz",
    "4",
    "Buzz",
    "Fizz",
    "7",
    "8",
    "Fizz",
    "Buzz",
    "11",
    "Fizz",
    "13",
    "14",
    "FizzBuzz"
]

题意：给定一个整数n，要求输出i（1<=i<=n）之间的所有整数；

如果i % 3 == 0 && i % 5== 0 ：输出"FizzBuzz"
如果i % 3 == 0 ：输出"Fizz"
如果i % 5 == 0 ：输出"Buzz"
否则输出i

解法：只要按照题目要求的判断整数i符合上面的哪种情况就输出对应的结果；

Java

class Solution {
    public List<String> fizzBuzz(int n) {
        List<String> result = new ArrayList<>();
        String threeTimes = "Fizz";
        String fiveTimes = "Buzz";
        String threeAndFiveTimes = "FizzBuzz";
        for (int i = 1; i <= n; i++) {
            if (i % 3 == 0 && i % 5 == 0) result.add(threeAndFiveTimes);
            else if (i % 3 == 0) result.add(threeTimes);
            else if (i % 5 == 0) result.add(fiveTimes);
            else result.add("" + i);
        }
        return result;
    }
}