HDU 1564 Play a game （简单博弈）-优快云博客

本文介绍了一个基于博弈论的游戏胜负判断问题。在一个n*n的棋盘上，两名玩家轮流将棋子移动到相邻未访问的位置，无法移动者判负。通过判断棋盘大小的奇偶性来决定赢家。

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New Year is Coming!
ailyanlu is very happy today! and he is playing a chessboard game with 8600.
The size of the chessboard is n*n. A stone is placed in a corner square. They play alternatively with 8600 having the first move. Each time, player is allowed to move the stone to an unvisited neighbor square horizontally or vertically. The one who can't make a move will lose the game. If both play perfectly, who will win the game?
Input
The input is a sequence of positive integers each in a separate line.
The integers are between 1 and 10000, inclusive,(means 1 <= n <= 10000) indicating the size of the chessboard. The end of the input is indicated by a zero.
Output
Output the winner ("8600" or "ailyanlu") for each input line except the last zero.
No other characters should be inserted in the output.
Sample Input
2
0
Sample Output
8600

题意：

从棋盘的一角开始，每人每次只能移动棋子到相邻没有经过的位置，直到不能移动棋子则为输。

题解：

很简单的博弈，也很好想，N为奇偶输赢不一样。

#include<iostream>
#include<algorithm>
using namespace std;
typedef long long LL;
int main()
{
    int n;
    while(cin>>n,n)
    {
        if(n%2)
            cout<<"ailyanlu"<<endl;
        else
            cout<<"8600"<<endl;
    }
    return 0;
}

转载于:https://www.cnblogs.com/orion7/p/7930529.html