-------Pokemon Master------很水-------

最新推荐文章于 2025-08-26 17:08:55 发布

weixin_33777877

最新推荐文章于 2025-08-26 17:08:55 发布

阅读量68

点赞数

CC 4.0 BY-SA版权

原文链接：http://www.cnblogs.com/A-FM/p/5096615.html

Calem和Serena决定在Pokemon World Championships之前进行一场有趣的宝可梦战斗练习，通过宝可梦的总重量来决定胜者。

A - Pokemon Master
Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%lld & %llu
Submit
 
Status
Description
Calem and Serena are pokemon masters. One day they decided to have a pokemon battle practice before Pokemon World Championships. Each of them has some pokemons in each's team. To make the battle more interesting, they decided to use a special rule to determine the winner: the team with heavier total weight will win the battle!

Input
There are multiple test cases. The first line of input contains an integer T indicating the number of test cases. For each test case:

The first line contains two integers N and M (1 <= N, M <= 6), which describes that Calem has N pokemons and Serena has M pokemons.

The second line contains N integers indicating the weight of Calem's pokemons. The third line contains M integers indicating the weight of Serena's pokemons. All pokemons' weight are in the range of [1, 2094] pounds.

Output
For each test case, output "Calem" if Calem's team will win the battle, or "Serena" if Serena's team will win. If the two team have the same total weight, output "Draw" instead.

Sample Input
1
6 6
13 220 199 188 269 1014
101 176 130 220 881 396
Sample Output
Serena

臭长题目其实没有多少技术含量.

意思就是第一行数据是测试案例数. 第二行是每个人拥有的拥有的什么鬼东西的重量,让你求出分别拥有的重量之和,谁的大谁就赢了.平局的话输出平局.

#include<stdio.h>
int main()
{
    int t, n, m;
    scanf("%d", &t);
    while (t--)
    {
        scanf("%d %d", &n, &m);
        int i, num, s1 = 0, s2 = 0;
        for (i = 0; i < n; i++)
        {
            scanf("%d", &num);
            s1 += num;
        }
        for (i = 0; i < m; i++)
        {
            scanf("%d", &num);
            s2 += num;
        }
        if (s1 == s2)
            printf("Draw");
        else
            printf(s1 > s2 ? "Calem" : "Serena");   //这里运用了三目运算符   很节省篇幅.......值得学习,如果?之前的条件成立的话,就执行紧挨着的,否则就执行:后面的
    }
    return 0;
}