ZOJ3776-Pokemon Master

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这是一个关于PokemonMaster Calem 和 Serena 的程序挑战题目解析，通过比较双方队伍中所有神奇宝贝的总重量来决定胜负。

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Pokemon Master

Time Limit: 2 Seconds Memory Limit: 65536 KB

Calem and Serena are pokemon masters. One day they decided to have a pokemon battle practice before Pokemon World Championships. Each of them has some pokemons in each's team. To make the battle more interesting, they decided to use a special rule to determine the winner: the team with heavier total weight will win the battle!

Input

There are multiple test cases. The first line of input contains an integer T indicating the number of test cases. For each test case:

The first line contains two integers N and M (1 <= N, M <= 6), which describes that Calem has N pokemons and Serena has M pokemons.

The second line contains N integers indicating the weight of Calem's pokemons. The third line contains M integers indicating the weight of Serena's pokemons. All pokemons' weight are in the range of [1, 2094] pounds.

Output

For each test case, output "Calem" if Calem's team will win the battle, or "Serena" if Serena's team will win. If the two team have the same total weight, output "Draw" instead.

Sample Input

1
6 6
13 220 199 188 269 1014
101 176 130 220 881 396

Sample Output

Serena

Author: JIANG, Kai
Source: The 11th Zhejiang Provincial Collegiate Programming Contest

题意：比较Calem和Serena手上牌的总和的大小，谁大就输出谁的名字，相同输出Draw

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <cstring>
#include <string>
#include <map>
#include <vector>
#include <queue>
#include <bitset>
#include <stack>

using namespace std;

int main()
{
    int t;
    int n,m;
    int a;
    scanf("%d",&t);
    while(t--)
    {
        scanf("%d %d",&n,&m);
        int sum1=0,sum2=0;
        for(int i=0;i<n;i++)
            scanf("%d",&a),sum1+=a;
        for(int i=0;i<m;i++)
            scanf("%d",&a),sum2+=a;
        if(sum1>sum2) printf("Calem\n");
        else if(sum1<sum2) printf("Serena\n");
        else printf("Draw\n");
    }
    return 0;
}