java-Spring HTTP客户端
我是Spring的新手,我需要Java应用程序通过HTTP(JSON,RESTful)连接到另一个API。 Spring框架是否具有JSON HTTP Rest Client之类的东西? Spring开发人员通常使用什么?
marcelorocks asked 2020-07-25T09:45:09Z
3个解决方案
44 votes
通过以下工作,我实现了所需的功能:
import org.springframework.http.HttpEntity;
import org.springframework.http.HttpHeaders;
import org.springframework.http.HttpMethod;
import org.springframework.http.HttpStatus;
import org.springframework.http.ResponseEntity;
import org.springframework.web.client.RestTemplate;
public class RestClient {
private String server = "http://localhost:3000";
private RestTemplate rest;
private HttpHeaders headers;
private HttpStatus status;
public RestClient() {
this.rest = new RestTemplate();
this.headers = new HttpHeaders();
headers.add("Content-Type", "application/json");
headers.add("Accept", "*/*");
}
public String get(String uri) {
HttpEntity requestEntity = new HttpEntity("", headers);
ResponseEntity responseEntity = rest.exchange(server + uri, HttpMethod.GET, requestEntity, String.class);
this.setStatus(responseEntity.getStatusCode());
return responseEntity.getBody();
}
public String post(String uri, String json) {
HttpEntity requestEntity = new HttpEntity(json, headers);
ResponseEntity responseEntity = rest.exchange(server + uri, HttpMethod.POST, requestEntity, String.class);
this.setStatus(responseEntity.getStatusCode());
return responseEntity.getBody();
}
public void put(String uri, String json) {
HttpEntity requestEntity = new HttpEntity(json, headers);
ResponseEntity responseEntity = rest.exchange(server + uri, HttpMethod.PUT, requestEntity, null);
this.setStatus(responseEntity.getStatusCode());
}
public void delete(String uri) {
HttpEntity requestEntity = new HttpEntity("", headers);
ResponseEntity responseEntity = rest.exchange(server + uri, HttpMethod.DELETE, requestEntity, null);
this.setStatus(responseEntity.getStatusCode());
}
public HttpStatus getStatus() {
return status;
}
public void setStatus(HttpStatus status) {
this.status = status;
}
}
marcelorocks answered 2020-07-25T09:45:23Z
16 votes
最简单的方法是使用RestTemplate,请在Spring官方博客上查看此文章:
RestTemplate是用于客户端HTTP访问的中央Spring类。
这是GET的示例:
String result = restTemplate.getForObject("http://example.com/hotels/{hotel}/bookings/{booking}", String.class, "42", "21");
Angular University answered 2020-07-25T09:45:52Z
1 votes
我做到了以下方式:
import java.io.FileReader;
import java.util.HashMap;
import java.util.Map;
import org.json.simple.JSONObject;
import org.json.simple.parser.JSONParser;
import org.springframework.http.HttpEntity;
import org.springframework.http.ResponseEntity;
import org.springframework.http.converter.StringHttpMessageConverter;
import org.springframework.util.LinkedMultiValueMap;
import org.springframework.util.MultiValueMap;
import org.springframework.web.client.RestTemplate;
public class PostRequestMain {
/**
* POST with Headers call using Spring RestTemplate
*
*
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
MultiValueMap headers = new LinkedMultiValueMap();
Map map = new HashMap();
map.put("Content-Type", "application/json");
headers.setAll(map);
Map req_payload = new HashMap();
req_payload.put("name", "piyush");
HttpEntity> request = new HttpEntity<>(req_payload, headers);
String url = "http://localhost:8080/portal-name/module-name/";
// Create a new RestTemplate instance
RestTemplate restTemplate = new RestTemplate();
// Add the String message converter
restTemplate.getMessageConverters().add(new StringHttpMessageConverter());
ResponseEntity response = restTemplate.postForEntity(url, request, String.class);
System.out.println(response);
}
private static void getPayloadMap() {
JSONParser parser = new JSONParser();
try {
Object obj = parser.parse(new FileReader("C:\\Piyush\\test.json"));
JSONObject jsonObject = (JSONObject) obj;
Map payLoadMap = new HashMap();
payLoadMap.putAll(jsonObject);
System.out.println(jsonObject);
} catch (Exception e) {
}
}
}
Piyush Mittal answered 2020-07-25T09:46:12Z