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最新推荐文章于 2022-10-05 23:06:04 发布

转载最新推荐文章于 2022-10-05 23:06:04 发布 · 65 阅读

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原文链接：http://www.cnblogs.com/20178303034nb/p/8591696.html

本文提供了两个C++程序实例：一是使用switch-case判断工作日与周末；二是实现数字反转功能。通过对这些代码的学习，读者可以加深对C++基础语法的理解。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

#include<iostream>
using namespace std;
int main()
{
    int day;
    cin>>day;
    switch(day)
    {
    case 1:
        cout<<"workday.Let's work hard"<<endl;
        break;
    case 2:
        cout<<"workday.Let's work hard"<<endl;
        break;
    case 3:
        cout<<"workday.Let's work hard"<<endl;
        break;
    case 4:
        cout<<"workday.Let's work hard"<<endl;
        break;
    case 5:
        cout<<"workday.Let's work hard"<<endl;
        break;
    case 6:
        cout<<"weekend.Let's have a rest"<<endl;
        break;
     case 7:
        cout<<"weekend.Let's have a rest"<<endl;
        break;
    }
    return 0;
}

#include<iostream>
using namespace std;
int main()
{ 
    int n,b,c=0;
    cout<<"Enter the number:";
    cin>>n;
    do{
        b=n%10;
        c=c*10+b;
        n/=10;
    }
    while(n!=0);
    cout<<c;
    cout<<endl;
    return 0;
}

实验总结与分析：

通过这个实验，让我熟悉了许多算法。

转载于:https://www.cnblogs.com/20178303034nb/p/8591696.html