JS URL Parser

为什么80%的码农都做不了架构师？>>>   

/**

*@param {string} url 完整的URL地址

*@returns {object} 自定义的对象

*@description 用法示例：var myURL = parseURL('http://abc.com:8080/dir/index.html?id=255&m=hello#top');

myURL.file='index.html'

myURL.hash= 'top'

myURL.host= 'abc.com'

myURL.query= '?id=255&m=hello'

myURL.params= Object = { id: 255, m: hello }

myURL.path= '/dir/index.html'

myURL.segments= Array = ['dir', 'index.html']

myURL.port= '8080'

yURL.protocol= 'http'

myURL.source= 'http://abc.com:8080/dir/index.html?id=255&m=hello#top'

*/

function parseURL(url) {

var a =  document.createElement('a');

a.href = url;

return {

source: url,

protocol: a.protocol.replace(':',''),

host: a.hostname,

port: a.port,

query: a.search,

params: (function(){

   var ret = {},

       seg = a.search.replace(/^\?/,'').split('&'),

       len = seg.length, i = 0, s;

   for (;i<len;i++) {

       if (!seg[i]) { continue; }

       s = seg[i].split('=');

       ret[s[0]] = s[1];

   }

   return ret;

})(),

file: (a.pathname.match(/\/([^\/?#]+)$/i) || [,''])[1],

hash: a.hash.replace('#',''),

path: a.pathname.replace(/^([^\/])/,'/$1'),

relative: (a.href.match(/tps?:\/\/[^\/]+(.+)/) || [,''])[1],

segments: a.pathname.replace(/^\//,'').split('/')

};

}

转载于:https://my.oschina.net/femdom/blog/26176