android http

本文提供了一个简单的Java实现,用于获取HTTP请求的状态码及JSON响应内容。通过两个示例方法,展示了如何使用HttpGet进行GET请求,并解析返回的JSON字符串。此外,还介绍了如何设置HTTP连接参数以提高请求效率。
public static String getHttpJSON(String url) {   
        HttpGet httpRequest = new HttpGet(url);   
        try {   
            HttpClient httpclient = new DefaultHttpClient();   
            HttpResponse httpResponse = httpclient.execute(httpRequest);   
   
            if (httpResponse.getStatusLine().getStatusCode() == HttpStatus.SC_OK) {   
                String jsonStr = EntityUtils.toString(httpResponse.getEntity(),   
                        "UTF-8");   
                return jsonStr;   
            }   
        } catch (Exception e) {   
            e.printStackTrace();   
            System.out.println("==============e.printStackTrace() : "   
                    + e.getMessage());   
        }   
        return null;   
    }   
   
    public static int getHttpStatus() {   
        int status = 0;   
        HttpGet httpRequest = new HttpGet(   
                "http://192.168.0.214/vote/AndroidConnServlet");   
        try {   
            HttpParams httpParameters = new BasicHttpParams();   
            HttpConnectionParams.setConnectionTimeout(httpParameters, 5000);   
            HttpConnectionParams.setSoTimeout(httpParameters, 5000);   
            HttpConnectionParams.setTcpNoDelay(httpParameters, true);   
               
            HttpClient httpclient = new DefaultHttpClient(httpParameters);   
            HttpResponse httpResponse = httpclient.execute(httpRequest);   
   
            status = httpResponse.getStatusLine().getStatusCode();   
        } catch (Exception e) {   
            e.printStackTrace();   
            System.out   
                    .println("==============connection wifi fail,e.printStackTrace() : "   
                            + e.getMessage());   
        }   
        return status;   
    }

转载于:https://my.oschina.net/xiahuawuyu/blog/111385

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