string test_json = "{\"name\":\"tom\",\"nickname\":\"tony\",\"sex\":\"male\",\"age\":20,\"email\":\"123@123.com\"}"; var o = JObject.Parse(yourJsonString); foreach (JToken child in o.Children()) { var property1 = child as JProperty; MessageBox.Show(property1.Name + ":" + property1.Value); } 多层Json var o = JObject.Parse(yourJsonString);
C#直接解析Json键值对
最新推荐文章于 2025-03-12 21:01:05 发布