python elementtree 命名空间,Python ElementTree默认名称空间？

最新推荐文章于 2024-06-29 07:48:27 发布

转载最新推荐文章于 2024-06-29 07:48:27 发布 · 110 阅读

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#python elementtree 命名空间

该博客探讨了如何在Python的ElementTree中处理默认未前缀的命名空间，指出直接使用默认命名空间的方法不可行，并推荐了通过赋予空命名空间非空名的技巧，同时提供了移除默认命名空间解析XML的示例。

Is there a way to define the default/unprefixed namespace in python ElementTree? This doesn't seem to work...

ns = {"":"http://maven.apache.org/POM/4.0.0"}

pom = xml.etree.ElementTree.parse("pom.xml")

print(pom.findall("version", ns))

Nor does this:

ns = {None:"http://maven.apache.org/POM/4.0.0"}

pom = xml.etree.ElementTree.parse("pom.xml")

print(pom.findall("version", ns))

This does, but then I have to prefix every element:

ns = {"mvn":"http://maven.apache.org/POM/4.0.0"}

pom = xml.etree.ElementTree.parse("pom.xml")

print(pom.findall("mvn:version", ns))

Using Python 3.5 on OSX.

EDIT: if the answer is "no", you can still get the bounty :-). I just want a definitive "no" from someone who's spent a lot of time using it.

解决方案

There is no straight-forward way to handle the default namespaces transparently. Assigning the empty namespace a non-empty name is a common solution, as you've already mentioned:

ns = {"mvn":"http://maven.apache.org/POM/4.0.0"}

pom = xml.etree.ElementTree.parse("pom.xml")

print(pom.findall("mvn:version", ns))

Note that lxml.etree does not allow the use of empty namespaces explicitly. You would get:

ValueError: empty namespace prefix is not supported in ElementPath

You can though, make things simpler, by removing the default namespace definition while loading the XML input data:

import xml.etree.ElementTree as ET

import re

with open("pom.xml") as f:

xmlstring = f.read()

# Remove the default namespace definition (xmlns="http://some/namespace")

xmlstring = re.sub(r'\sxmlns="[^"]+"', '', xmlstring, count=1)

pom = ET.fromstring(xmlstring)

print(pom.findall("version"))