java 36 进制_Java实现的26进制转换

今天看到有个羣聊里分享了一道面试题，感觉挺有意思的就尝试了一下，代码如下：

public class Hex26 {

// 进制基础值，也可以修改为'a'

private final static char A = 'A';

public static void main(String[] args) {

int[] arr = {

0, 1, 2,

25, 26, 27,

51, 52, 53,

77, 78, 79

};

for (int i : arr) {

String str = toHex26(i);

System.out.printf("old: %d, str: %s, int: %d \n", i, str, compareHex26(str));

}

}

private static String toHex26(int i) {

StringBuilder sb = new StringBuilder();

if (i == 0) {

sb.append(A);

return sb.toString();

}

int divide = i / 26;

if (divide > 0) {

for (int j = 0; j < divide; j++) {

sb.append(A);

}

}

int m = i % 26;

char c = (char)(A + m);

sb.append(c);

return sb.toString();

}

private static int compareHex26(String hex) {

int i = 0, j = 0;

for (; j < hex.length() - 1; j++) {

char c = hex.charAt(j);

int diff = c - A;

if (diff == 0) {

i += 26;

}else {

i += diff;

}

}

if (j == hex.length()-1) {

char c = hex.charAt(j);

i += c - A;

}

return i;

}

}

输出结果如下：

old: 0, str: A, int: 0

old: 1, str: B, int: 1

old: 2, str: C, int: 2

old: 25, str: Z, int: 25

old: 26, str: AA, int: 26

old: 27, str: AB, int: 27

old: 51, str: AZ, int: 51

old: 52, str: AAA, int: 52

old: 53, str: AAB, int: 53

old: 77, str: AAZ, int: 77

old: 78, str: AAAA, int: 78

old: 79, str: AAAB, int: 79

over~