zoj 2388 Beat the Spread!

最新推荐文章于 2021-11-15 22:00:48 发布

转载最新推荐文章于 2021-11-15 22:00:48 发布 · 77 阅读

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原文链接：http://www.cnblogs.com/qinduanyinghua/p/6532987.html

本文介绍了一个有趣的问题：根据足球比赛的总得分和两队得分的绝对差值来推算最终比分。通过简单的数学方法，我们可以解决这个问题并实现了一个C++程序来自动计算可能的比分。

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Beat the Spread!

Time Limit: 2 Seconds Memory Limit: 65536 KB

Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.

Given the winning numbers for each type of bet, can you deduce the final scores?

Input

The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.

Output

For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing "impossible". Recall that football scores are always non-negative integers.

Sample Input

2
40 20
20 40

Sample Output

30 10
impossible

 1 #include <iostream>
 2 using namespace std;
 3 int main(){
 4     int n, s, d;
 5     //x + y = s;
 6     //x - y = d;
 7     int x, y;//因为是绝对差，所以直接假定x大，y小
 8     cin >> n;
 9     while(n--){
10         cin >> s >> d;
11         //x,y必须为整数,由方程得2x = s + d;故s + d为偶数 
12         if((s + d) % 2 != 0){
13             cout << "impossible" << endl;
14             continue;
15         }
16         else
17             x = (s + d) / 2;
18         y = s - x;
19         if(y < 0)
20             cout << "impossible" << endl;
21         else
22             cout << x << " " << y << endl;
23     }
24     return 0;
25 }

转载于:https://www.cnblogs.com/qinduanyinghua/p/6532987.html