zoj2388 Beat the Spread!

破解比分之谜

最新推荐文章于 2019-06-30 01:30:45 发布

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本文介绍了一个简单的算法问题，即根据比赛最终得分的总和及绝对差值，逆向推算出具体的两队得分。通过判断条件(s + d) % 2 == 0来确保能够找到合理的解决方案。

Beat the Spread!

Time Limit: 2000MS

Memory Limit: 65536KB

64bit IO Format: %lld & %llu

Submit Status

Description

Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.

Given the winning numbers for each type of bet, can you deduce the final scores?

Input

The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.

Output

For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing "impossible". Recall that football scores are always non-negative integers.

Sample Input

2
40 20
20 40

Sample Output

30 10
impossible

Source

University of Waterloo Local Contest 2005.02.05

分析：

水题。注意判断(s+d)%2==0就可以了。

ac代码：

#include <iostream>
#include<cstdio>
using namespace std;

int main()
{
    int n,s,d;
    int x,y;
    scanf("%d",&n);
    while(n--)
    {
        scanf("%d%d",&s,&d);
        if(s>=d&&(s+d)%2==0)//注意判断(s+d)%2==0
        printf("%d %d\n",(s+d)/2,(s-d)/2);
        else
        printf("impossible\n");
    }
    return 0;
}